-1.5=4x+-4.9x^2

Solution for -1.5=4x+-4.9x^2 equation:

-1.5=4x+-4.9x^2

We move all terms to the left:

-1.5-(4x+-4.9x^2)=0

We use the square of the difference formula

-(4x-4.9x^2)-1.5=0

We get rid of parentheses

4.9x^2-4x-1.5=0

a = 4.9; b = -4; c = -1.5;
Δ = b2-4ac
Δ = -42-4·4.9·(-1.5)
Δ = 45.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-\sqrt{45.4}}{2*4.9}=\frac{4-\sqrt{45.4}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+\sqrt{45.4}}{2*4.9}=\frac{4+\sqrt{45.4}}{9.8}
$